Lorraine Posted January 10, 2015 Share Posted January 10, 2015 Here's one I am scratching my head on: how old was Geddy at the start of the 30th Anniverary Tour?I think he was younger than he was at the end of it. "He was so much older then,He's younger than that now." Or maybe not...It's taken me from the time you posted this until this moment to remember where you got that from - The Byrds. Yes! I'm surprised you didn't get that right away. :rfl: :rfl: :rfl: Are you kidding me? At one time, yes. No longer. Link to comment Share on other sites More sharing options...
Blue J Posted January 10, 2015 Share Posted January 10, 2015 Oh, I guarantee there are some old tapes or reel to reels from those early shows...........somewhere. That would be quite a little treasure for a future box set or something. But you're probably right. It won't happen. Link to comment Share on other sites More sharing options...
Blue J Posted January 10, 2015 Share Posted January 10, 2015 Here's one I am scratching my head on: how old was Geddy at the start of the 30th Anniverary Tour?I think he was younger than he was at the end of it. "He was so much older then,He's younger than that now." Or maybe not...It's taken me from the time you posted this until this moment to remember where you got that from - The Byrds. Yes! I'm surprised you didn't get that right away. :rfl: :rfl: :rfl: Are you kidding me? At one time, yes. No longer. Maybe I should have included a couple of these --> :musicnote: :musicnote: Link to comment Share on other sites More sharing options...
Lorraine Posted January 10, 2015 Share Posted January 10, 2015 Here's one I am scratching my head on: how old was Geddy at the start of the 30th Anniverary Tour?I think he was younger than he was at the end of it. "He was so much older then,He's younger than that now." Or maybe not...It's taken me from the time you posted this until this moment to remember where you got that from - The Byrds. Yes! I'm surprised you didn't get that right away. :rfl: :rfl: :rfl: Are you kidding me? At one time, yes. No longer. Maybe I should have included a couple of these --> :musicnote: :musicnote:I didn't make myself clear. I knew it was from an old song, but I couldn't remember which one. It took all those hours for it to come to me. Link to comment Share on other sites More sharing options...
Pale Facsimile Posted January 10, 2015 Share Posted January 10, 2015 This thread just reminds me I haven't done squat with my life...at my current age, the members of... -RUSH would've been working on Power Windows...-Metallica would've been finishing up the never-ending Black Album tour...-Queen would've been working on Jazz...-Green Day would've just released American Idiot... Meanwhile, I've...hmmm...let's see...self-published one book of poetry. Go me....Oh and drank a lot of Diet Pepsi! :d13: Link to comment Share on other sites More sharing options...
Disk98 Posted January 10, 2015 Share Posted January 10, 2015 (edited) At my age they were already formed. Edited January 10, 2015 by Disk98 Link to comment Share on other sites More sharing options...
LedRush Posted January 10, 2015 Share Posted January 10, 2015 Here's one I am scratching my head on: how old was Geddy at the start of the 30th Anniverary Tour?I think he was younger than he was at the end of it. "He was so much older then,He's younger than that now." Or maybe not...It's taken me from the time you posted this until this moment to remember where you got that from - The Byrds. Yes! I'm surprised you didn't get that right away. Um....Mr. Zimmerman would like to have a talk with you guys. Link to comment Share on other sites More sharing options...
Disk98 Posted January 10, 2015 Share Posted January 10, 2015 (edited) I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = ( {[12y - (12 - m)] - 23,341} ÷ 12 ) - 8Round a to nearest whole number, as this is only approximate. (0.5 always rounds up to 1) This month is 1/2015, so y = 2,015 and m = 1. a = ( {[12 • 2,015 - (12 - 1)] - 23,341} ÷ 12 ) - 8a = [(24,180 - 11 - 23,341) ÷ 12] - 8a = (828 ÷ 12) - 8a = 69 - 8a = 61 Edited January 10, 2015 by Disk98 Link to comment Share on other sites More sharing options...
LedRush Posted January 10, 2015 Share Posted January 10, 2015 I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = [12y - (12 - m)] - Wow, you are one of the smartest men ever born. Link to comment Share on other sites More sharing options...
Disk98 Posted January 10, 2015 Share Posted January 10, 2015 I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = [12y - (12 - m)] - Wow, you are one of the smartest men ever born.Not finished. I clicked post by mistake. It's edited now. :) Link to comment Share on other sites More sharing options...
LedRush Posted January 10, 2015 Share Posted January 10, 2015 I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = [12y - (12 - m)] - Wow, you are one of the smartest men ever born.Not finished. I clicked post by mistake. It's edited now. :)Do you always find roundabout, ridiculously complicated ways to solve exceptionally simple math equations? Link to comment Share on other sites More sharing options...
Disk98 Posted January 10, 2015 Share Posted January 10, 2015 I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = [12y - (12 - m)] - Wow, you are one of the smartest men ever born.Not finished. I clicked post by mistake. It's edited now. :)Do you always find roundabout, ridiculously complicated ways to solve exceptionally simple math equations?Sometimes. Link to comment Share on other sites More sharing options...
LedRush Posted January 10, 2015 Share Posted January 10, 2015 Fair enough. Link to comment Share on other sites More sharing options...
Disk98 Posted January 10, 2015 Share Posted January 10, 2015 (edited) I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = ( {[12y - (12 - m)] - 23,341} ÷ 12 ) - 8Round a to nearest whole number, as this is only approximate. (0.5 always rounds up to 1) This month is 1/2015, so y = 2,015 and m = 1. a = ( {[12 • 2,015 - (12 - 1)] - 23,341} ÷ 12 ) - 8a = [(24,180 - 11 - 23,341) ÷ 12] - 8a = (828 ÷ 12) - 8a = 69 - 8a = 61This doesn't work out very well. I'll find another equation that will work better. Stay posted! Edited January 10, 2015 by Disk98 Link to comment Share on other sites More sharing options...
Lorraine Posted January 10, 2015 Share Posted January 10, 2015 I think I solved the equation after hours of trying. Here it is: x year and month - month 7 in the year 1953 AD.You better get someone here to help you. Disk98 has a high IQ. I'm sure he would be happy to help you out. :) a = approximate age in yearsy = given yearm = given month a = ( {[12y - (12 - m)] - 23,341} ÷ 12 ) - 8Round a to nearest whole number, as this is only approximate. (0.5 always rounds up to 1) This month is 1/2015, so y = 2,015 and m = 1. a = ( {[12 • 2,015 - (12 - 1)] - 23,341} ÷ 12 ) - 8a = [(24,180 - 11 - 23,341) ÷ 12] - 8a = (828 ÷ 12) - 8a = 69 - 8a = 61This doesn't work out very well. I'll find another equation that will work better. Stay posted!Alrightie Link to comment Share on other sites More sharing options...
Lorraine Posted January 10, 2015 Share Posted January 10, 2015 (edited) Dropped my popcorn. Edited January 10, 2015 by Lorraine Link to comment Share on other sites More sharing options...
Narps Posted January 10, 2015 Share Posted January 10, 2015 Dropped my popcorn.The 5 second rule applies.... :cheers: Link to comment Share on other sites More sharing options...
Citizen of the World Posted January 10, 2015 Share Posted January 10, 2015 Zumbi, by the time Geddy was your age (24), Rush had already recorded AFTK and was in the midst of composing Hemispheres.I wish I'd have thought of writing AFTK and Hemispheres when I was 24You will, Your Lion, you will Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now